Lection 1 homework

README.md

@@ -1 +1 @@
-# JS-Proffessional-03-2023
+OTUS JavaScript Proffessional course repo

src/carrying.js

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+let sum = (arg) => {
+  return (arg === undefined) ? 0 : function inner(innerArg) {
+    arg += innerArg | 0;    
+    return (innerArg === undefined) ? arg : inner;
+  };
+}
+
+console.log(sum(12)(13)(14)(0)(1)()); //40
+console.log(sum()); //0

src/list.js

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+//it just fast-borned simple algorithm from the head, I think it does not too fast and memory optimized
+
+//uncomment items for larger result list 
+//"r" extends list for "v"
+//"d" extends list for "d, x, y, t, l, m, z"
+//"d + l" extends for "d, x, y, t, l, m, z, f, g"
+//uncommenting only "l" extends for none
+let prodsList = [["q", "w", "a"], ["a", "b"/*, "d"*/], ["a","c"], ["q", "e"], ["q", "r"], ["x", "y", "z"], ["x", "d"], ["z", "m"], ["f",  "g"/*, "l"*/], ["t", "l", "y"], [/*"r", */"v"]];
+
+//if result is an object, algorithm must to be too match faster, because "indexOf" did not used
+let result = [];
+
+let uniProds = {};
+let mostPopular = {name : "",
+                   popularity : 0}
+
+prodsList.forEach((list) => {
+	if (list.length < 2) {
+		return;
+	}
+
+	for (let name of list) {
+		uniProds[name] ??= { childs : {}, name : name, popularity : 0 };
+		let prod = uniProds[name];    	
+		(prod.popularity ++ >= mostPopular.popularity) && (mostPopular = prod);
+		//element itself do add to childs tree alwais, its necessary (!!)
+		list.forEach((el) => {
+			uniProds[el] ??= { childs : {}, name : el, popularity : 0 };
+			prod.childs[el] ??= uniProds[el];
+			prod = uniProds[el];
+		});
+	}
+});
+
+(getResult = (prod) => {
+	if (prod.childs) {
+		//if recursion does find existing item, simple waste this tree branch
+		for (let name in prod.childs)
+		//if it does find non-existing item, adding it to the result list
+		if (result.indexOf(prod.childs[name].name) < 0) {
+			result.push(prod.childs[name].name);
+			getResult(prod.childs[name]);
+		}
+	}
+	return result;
+})(mostPopular).sort((a, b) => {
+	return a > b; //sort result list by name
+	// return uniProds[a].popularity < uniProds[b].popularity; //sort result list by popularity
+});
+
+console.log(result);