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<h2><a href="https://leetcode.com/problems/array-reduce-transformation">Array Reduce Transformation</a></h2> <img src='https://img.shields.io/badge/Difficulty-Easy-brightgreen' alt='Difficulty: Easy' /><hr><p>Given an integer array <code>nums</code>, a reducer function <code>fn</code>, and an initial value <code>init</code>, return the final result obtained by executing the <code>fn</code> function on each element of the array, sequentially, passing in the return value from the calculation on the preceding element.</p> | ||
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<p>This result is achieved through the following operations: <code>val = fn(init, nums[0]), val = fn(val, nums[1]), val = fn(val, nums[2]), ...</code> until every element in the array has been processed. The ultimate value of <code>val</code> is then returned.</p> | ||
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<p>If the length of the array is 0, the function should return <code>init</code>.</p> | ||
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<p>Please solve it without using the built-in <code>Array.reduce</code> method.</p> | ||
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<p> </p> | ||
<p><strong class="example">Example 1:</strong></p> | ||
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<pre> | ||
<strong>Input:</strong> | ||
nums = [1,2,3,4] | ||
fn = function sum(accum, curr) { return accum + curr; } | ||
init = 0 | ||
<strong>Output:</strong> 10 | ||
<strong>Explanation:</strong> | ||
initially, the value is init=0. | ||
(0) + nums[0] = 1 | ||
(1) + nums[1] = 3 | ||
(3) + nums[2] = 6 | ||
(6) + nums[3] = 10 | ||
The final answer is 10. | ||
</pre> | ||
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<p><strong class="example">Example 2:</strong></p> | ||
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<pre> | ||
<strong>Input:</strong> | ||
nums = [1,2,3,4] | ||
fn = function sum(accum, curr) { return accum + curr * curr; } | ||
init = 100 | ||
<strong>Output:</strong> 130 | ||
<strong>Explanation:</strong> | ||
initially, the value is init=100. | ||
(100) + nums[0] * nums[0] = 101 | ||
(101) + nums[1] * nums[1] = 105 | ||
(105) + nums[2] * nums[2] = 114 | ||
(114) + nums[3] * nums[3] = 130 | ||
The final answer is 130. | ||
</pre> | ||
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<p><strong class="example">Example 3:</strong></p> | ||
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<pre> | ||
<strong>Input:</strong> | ||
nums = [] | ||
fn = function sum(accum, curr) { return 0; } | ||
init = 25 | ||
<strong>Output:</strong> 25 | ||
<strong>Explanation:</strong> For empty arrays, the answer is always init. | ||
</pre> | ||
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<p> </p> | ||
<p><strong>Constraints:</strong></p> | ||
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<ul> | ||
<li><code>0 <= nums.length <= 1000</code></li> | ||
<li><code>0 <= nums[i] <= 1000</code></li> | ||
<li><code>0 <= init <= 1000</code></li> | ||
</ul> |