Full time bug

problems/01-get-keys.js

@@ -3,7 +3,7 @@ Write a function called getKeys(obj) that iterates through the object and
 returns an array of the object's keys only.
 */
 
-// Your code here 
+// Your code here
 
 // const obj = {
 //   first: "1",

problems/02-get-2c-keys.js

@@ -3,7 +3,7 @@ Write a function called get2CKeys(obj) that iterates through the object and
 returns an array of the object's keys that have values with at least 2 'c's.
 */
 
-// Your code here 
+// Your code here
 
 // const obj = {
 //   red: 'circle',

problems/03-get-values.js

@@ -3,7 +3,7 @@ Write a function called getValues(obj) that iterates through the object and
 returns an array of the object's values only.
 */
 
-// Your code here 
+// Your code here
 
 // const car = {
 //   make: 'Toyota',

problems/04-object-to-array.js

@@ -5,7 +5,7 @@ is formatted such that the first element is the key and the second element is
 the value.
 */
 
-// Your code here 
+// Your code here
 
 // let bootcamp = {
 //   name: "App Academy",

problems/05-object-to-array-sum.js

@@ -5,7 +5,7 @@ nested array is formatted such that the first element is the key and the second
 element is the sum of all the numbers in the array value.
 */
 
-// Your code here 
+// Your code here
 
 // let populations = {
 //   neighborhood1: [10, 1, 3, 6],

problems/06-refactor-get-vowel-keys.js

@@ -1,6 +1,6 @@
 /*
 Given the function getVowelKeys(obj) below that iterates through an object and
-returns all values associated with keys that are vowels using Object.keys(),
+returns all values associated with keys that have vowels using Object.keys(),
 refactor the code to not use Object.keys() but still passes the test specs.
 
 Key point here is to note how there are multiple ways to iterate through an

problems/07-common-keys.js

@@ -4,7 +4,7 @@ common keys between the two input objects, obj1 and obj2.
 */
 
 function commonKeys(obj1, obj2) {
-  // Your code here 
+  // Your code here
 }
 
 // console.log(commonKeys(

problems/08-count-characters.js

@@ -5,7 +5,7 @@ the characters show up in the string as values.
 */
 
 function countCharacters(str) {
-  // Your code here 
+  // Your code here
 }
 
 // console.log(countCharacters('hello')); // => { h: 1, e: 1, l: 2, o: 1}

problems/09-count-elements.js

@@ -5,7 +5,7 @@ the elements show up in the string as values.
 */
 
 function countElements(arr) {
-  // Your code here 
+  // Your code here
 }
 
 // console.log(countElements(

problems/10-get-scores.js

@@ -6,7 +6,7 @@ should be the value of the score key in the nested objects in the input array.
 */
 
 function getScores(arr) {
-  // Your code here 
+  // Your code here
 }
 
 // console.log(getScores([

problems/11-is-palindrome-anagram.js

@@ -0,0 +1,26 @@
+/*
+Given a sentence, write a function called isPalindromeAnagram that returns true if the
+sentence can be rearranged into a palindrome and false if not. Ignore whitespace
+and assume all characters are lowercase.
+
+Note: A palindrome is a sequence that reads the same backwards as is does
+forward.
+*/
+
+const isPalindromeAnagram = sentence => {
+  // Your code here
+};
+
+// console.log(isPalindromeAnagram('pop'));               // true;
+// console.log(isPalindromeAnagram('kayak'));             // true
+// console.log(isPalindromeAnagram('yo banana boy'));     // true
+// console.log(isPalindromeAnagram('this is the truth')); // false
+// console.log(isPalindromeAnagram('abab'));              // true
+// // because 'abab' can be rearranged into a palindrome, 'abba'
+
+
+/******************** DO NOT MODIFY ANY CODE BELOW THIS LINE *****************/
+
+try {
+  module.exports = isPalindromeAnagram;
+} catch {}

problems/12-are-anagrams.js

@@ -7,7 +7,7 @@ CHALLENGE: Can you do it with just one object?
 */
 
 function areAnagrams(word1, word2) {
-  // Your code here 
+  // Your code here
 }
 
 // console.log(areAnagrams("cat", "act"));          // true

test/11-is-palindrome-anagram-spec.js

@@ -0,0 +1,21 @@
+const chai = require("chai");
+const expect = chai.expect;
+const isPalindromeAnagram = require("../problems/11-is-palindrome-anagram");
+
+describe("isPalindromeAnagram", function() {
+  it("isPalindromeAnagram('pop') returns true", function () {
+    expect(isPalindromeAnagram('pop')).to.be.true;
+  });
+  it("isPalindromeAnagram('kayak') returns true", function () {
+    expect(isPalindromeAnagram('kayak')).to.be.true;
+  });
+  it("isPalindromeAnagram('yo banana boy') returns true", function () {
+    expect(isPalindromeAnagram('yo banana boy')).to.be.true;
+  });
+  it("isPalindromeAnagram('this is the truth') returns false", function () {
+    expect(isPalindromeAnagram('this is the truth')).to.be.false;
+  });
+  it("isPalindromeAnagram('abab') returns true", function () {
+    expect(isPalindromeAnagram('abab')).to.be.true;
+  });
+});