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fix: 编辑计划任务和病毒扫描告警问题处理 #7047
fix: 编辑计划任务和病毒扫描告警问题处理 #7047
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err := xpack.UpdateAlert(updateAlert) | ||
if err != nil { | ||
return err | ||
} | ||
} | ||
return nil | ||
} |
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这个函数主要负责更新一个名叫"clams"的告警(alert)。在当前版本中,代码是有效的,并且没有发现需要改进的地方。
然而,在2021年之前可能存在一些问题:
- 应该使用
err.Error()
来打印错误信息,避免将错误写入日志。 - 可以更改为
var updateAlert = dto.CreateOrUpdateAlert{}
来简化代码。 - 如果传参中的字段不全,最好抛出异常而不是直接返回nil。
总体来说,如果只考虑性能和效率的影响,并没有明显的不合规或问题。
关于优化建议:保持简洁、清晰的编程风格,并经常进行单元测试。
err = xpack.UpdateAlert(updateAlert) | ||
if err != nil { | ||
return err | ||
} | ||
} | ||
return nil | ||
} |
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这个代码没有明显的问题或需要改进的地方。它看起来已经是最新版本,并且逻辑已经正确无误。然而,为了进一步完善性能和可读性,可以考虑:
- 将函数名为
CreateOrUpdateAlert
。 - 函数签名为一个参数是类型为*dto.CronjobUpdate请求体的一个结构体的对象。
func (u *CronjobService) UpdateByID(id uint, req dto.CronjobUpdateRequest) error {
if err := validate(req); err != nil {
return errors.Wrap(err, "request validation failed")
}
updateAlert := dto.CreateOrUpdateAlert{
AlertTitle: req.GetAlert.Title(),
// 可以将其他字段从req复制到updateAlert的字段中...
AlertType: cronModel.Type,
AlertCount: int(req.GetAlert.Count()),
EntryID: id.ToString()
},
result, _, err
if !errors.IsNotFoundError(err){
}
```
3. 建议在每次操作之前验证输入数据。
4. 如果有更多cronjobs存在,则推荐使用分页查找/删除的方法而不是更新整个collection中的所有元素,在性能优化方面有很大的提升空间。
这是最基础的更改思路,更具体的改进建议取决于需求及实际应用场景的具体情况。
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/lgtm
/approve |
[APPROVALNOTIFIER] This PR is APPROVED This pull-request has been approved by: wanghe-fit2cloud The full list of commands accepted by this bot can be found here. The pull request process is described here
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Refs #7039