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Bead division problem #18
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Hi,
and then running the code is slightly different:
You can also fine tune the results of the parameterization yourself by replacing certain assignments if you know that a certain bead type makes more sense for that specific fragment based on more relevant properties for your system (rather than the octanol/water partitioning free energy). |
Thanks for your patient answer. I will try it. |
Hi **;;;; GENERATED WITH auto-martini [moleculetype] [atoms] [bonds] It is 13:2 (heavy atoms to bead ratio), I mean how reliable is this? Any comments? It will be helpful if you can also give some other examples (of-course butanol) where people used something similar. |
Using the
maybe try using smiles string rather than sdf files, as we've done more tests with the former. |
What I am getting using smiles string is : ;;;; GENERATED WITH auto-martini [moleculetype] [atoms] [bonds] [angles] Bead type 1 is different. |
Please confirm which version of the code you are using. Tristan's result (which I also get) is from using the |
Sure. Thanks a lot for the explanation. I have understood the difference now. Comment - The script is very useful :) |
I found that the latest version is not the same as the old version of the beads.
Such as the molecular:O(CCOC(=O)c1ccccc1)CO
The new version divides:SN0 SN0 SN0 P1 P1
The old:SC5 SC5 SC5 P1 P1
That is,the new one divides benzene into SN0 SN0 SN0.
In addition,some of the beads were not 4-1 or 3-1 mapping,such as(SMILES:c1cc(ccc1)C(=O)OCCOCO):
[atoms]
; id type resnr residu atom cgnr charge smiles
1 SC5 1 HCB2 S01 1 0 ; [H]c1cc([H])c([H])c([H])c1[H]
2 SC5 1 HCB2 S02 2 0 ; [H]c1cc([H])c([H])c([H])c1[H]
3 SC5 1 HCB2 S03 3 0 ; [H]c1cc([H])c([H])c([H])c1[H]
4 P1 1 HCB2 P01 4 0 ; OC=O
5 P1 1 HCB2 P02 5 0 ; [H]OC([H])([H])OC([H])([H])C([H])[H]
Another group [H]OC([H])([H])C([H])[H]OC=O was divided into P2,that is,there are 3-1, 4-1,5-1,6-1 in one molecule.
I wonder if this division is possible.
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