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As far as I understand the code, all clock calculations in freeze() use the last sysclk value specified with either the sysclk() or the sysclk_with_pll() methods, but if sysclk_wit_pll() has been called at least once, the actual sysclk used is the output_clock as calculated in let output_clock = vco / r;, which can be a completely different value
The text was updated successfully, but these errors were encountered:
As far as I understand the code, all clock calculations in
freeze()
use the last sysclk value specified with either thesysclk()
or thesysclk_with_pll()
methods, but ifsysclk_wit_pll()
has been called at least once, the actual sysclk used is the output_clock as calculated in let output_clock = vco / r;, which can be a completely different valueThe text was updated successfully, but these errors were encountered: