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We should fuzz statistics by computing all possible stats on an array via array.statistics.compute_all(all::<Stat>()) or some such, canonicalizing that array, and then calling compute_statistics on the canonicalized array (one by one).
If the statistic is present in the first set, it should also be present and with equal value in the second set.
The text was updated successfully, but these errors were encountered:
We should fuzz statistics by computing all possible stats on an array via
array.statistics.compute_all(all::<Stat>())
or some such, canonicalizing that array, and then callingcompute_statistics
on the canonicalized array (one by one).If the statistic is present in the first set, it should also be present and with equal value in the second set.
The text was updated successfully, but these errors were encountered: