{leetcode}/problems/first-unique-character-in-a-string/[LeetCode - First Unique Character in a String^]
还是要善用 Map
来统计字符数量!
Given a string, find the first non-repeating character in it and return it’s index. If it doesn’t exist, return -1.
Examples:
s = "leetcode" return 0. s = "loveleetcode", return 2.
Note: You may assume the string contain only lowercase letters.
通过解法是再次遍历字符串,思考如何遍历字母表来获取第一个唯一字符的位置。
- 一刷
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link:{sourcedir}/_0387_FirstUniqueCharacterInAString.java[role=include]
- 二刷
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link:{sourcedir}/_0387_FirstUniqueCharacterInAString_2.java[role=include]