-
Notifications
You must be signed in to change notification settings - Fork 242
/
Copy pathNodes without siblings.cpp
71 lines (54 loc) · 1.75 KB
/
Nodes without siblings.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
/*
Nodes without sibling
For a given Binary Tree of type integer, print all the nodes without any siblings.
Input Format:
The first and the only line of input will contain the node data, all separated by a single space. Since -1 is used as an indication whether the
left or right node data exist for root, it will not be a part of the node data.
Output Format:
The only line of output prints the node data in a top to down fashion with reference to the root.
Node data in the left subtree will be printed first and then the right subtree.
A single space will separate them all.
Constraints:
1 <= N <= 10^5
Where N is the total number of nodes in the binary tree.
Time Limit: 1 second
Sample Input 1:
5 6 10 2 3 -1 -1 -1 -1 -1 9 -1 -1
Sample Output 1:
9
Sample Input 2:
2 4 5 6 -1 -1 7 20 30 80 90 -1 -1 -1 -1 -1 -1 -1 -1
Sample Output 2:
6 7
*/
/************************************************************
Following is the Binary Tree node structure
template <typename T>
class BinaryTreeNode
{
public :
T data;
BinaryTreeNode<T> *left;
BinaryTreeNode<T> *right;
BinaryTreeNode(T data)
{
this -> data = data;
left = NULL;
right = NULL;
}
};
************************************************************/
void printNodesWithoutSibling(BinaryTreeNode<int> *root) {
// Write your code here
//corner case
if(root == NULL) {
return;
}
if(root -> left == NULL and root -> right) {
cout << root -> right -> data << " ";
} else if (root -> left and root -> right == NULL) {
cout << root -> left -> data << " ";
}
printNodesWithoutSibling(root -> left);
printNodesWithoutSibling(root -> right);
}