Skip to content
New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

RemoveAccessTo is buggy? #27

Open
neongreen opened this issue Aug 20, 2020 · 3 comments
Open

RemoveAccessTo is buggy? #27

neongreen opened this issue Aug 20, 2020 · 3 comments

Comments

@neongreen
Copy link
Collaborator


RemoveAccessTo l ((l := t) ': lts) = RemoveAccessTo l lts
RemoveAccessTo q ((l := t) ': lts) = (l := t) ': RemoveAccessTo l lts
RemoveAccessTo q '[] = '[]


Shouldn't it be RemoveAccessTo q lts in the second equation?

@agrafix
Copy link
Owner

agrafix commented Aug 21, 2020

Ah, nice catch... Yes!

@neongreen
Copy link
Collaborator Author

Given that it doesn't work, I wonder whether it was necessary at all..?

@agrafix
Copy link
Owner

agrafix commented Aug 29, 2020

Yeah afaik it is only used in type instances so maybe we can nix it.

Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment
Labels
None yet
Projects
None yet
Development

No branches or pull requests

2 participants