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line_clip.h
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line_clip.h
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#pragma once
#include "vector.h"
// From https://www.wikiwand.com/en/Cohen%E2%80%93Sutherland_algorithm
// Thank you wikipedia!
// Cohen–Sutherland clipping algorithm clips a line from
// P0 = (x0, y0) to P1 = (x1, y1) against a rectangle with
// diagonal from (xmin, ymin) to (xmax, ymax).
using OutCode = int;
constexpr int OC_INSIDE = 0;
constexpr int OC_LEFT = 1;
constexpr int OC_RIGHT = 2;
constexpr int OC_BOTTOM = 4;
constexpr int OC_TOP = 8;
DEVICE
OutCode compute_out_code(const Vector2 &v) {
OutCode code;
code = OC_INSIDE; // initialised as being inside of [[clip window]]
if (v[0] < 0.f) { // to the left of clip window
code |= OC_LEFT;
} else if (v[0] > 1.f) { // to the right of clip window
code |= OC_RIGHT;
}
if (v[1] < 0.f) { // below the clip window
code |= OC_BOTTOM;
} else if (v[1] > 1.f) { // above the clip window
code |= OC_TOP;
}
return code;
};
DEVICE
bool clip_line(const Vector2 &v0, const Vector2 &v1,
Vector2 &v0c, Vector2 &v1c) {
// Compute the bit code for a point (x, y) using the clip rectangle
// bounded diagonally by (xmin, ymin), and (xmax, ymax)
// compute outcodes for P0, P1, and whatever point lies outside the clip rectangle
OutCode outcode0 = compute_out_code(v0);
OutCode outcode1 = compute_out_code(v1);
bool accept = false;
v0c = v0;
v1c = v1;
while (true) {
if (!(outcode0 | outcode1)) {
// bitwise OR is 0: both points inside window; trivially accept and exit loop
accept = true;
break;
} else if (outcode0 & outcode1) {
// bitwise AND is not 0: both points share an outside zone (LEFT, RIGHT, TOP,
// or BOTTOM), so both must be outside window; exit loop (accept is false)
break;
} else {
// failed both tests, so calculate the line segment to clip
// from an outside point to an intersection with clip edge
auto v = Vector2{0, 0};
// At least one endpoint is outside the clip rectangle; pick it.
OutCode outcodeOut = outcode0 ? outcode0 : outcode1;
// Now find the intersection point;
// use formulas:
// slope = (y1 - y0) / (x1 - x0)
// x = x0 + (1 / slope) * (ym - y0), where ym is ymin or ymax
// y = y0 + slope * (xm - x0), where xm is xmin or xmax
// No need to worry about divide-by-zero because, in each case, the
// outcode bit being tested guarantees the denominator is non-zero
if (outcodeOut & OC_TOP) { // point is above the clip window
v[0] = v0c[0] + (v1c[0] - v0c[0]) * (1.f - v0c[1]) / (v1c[1] - v0c[1]);
v[1] = 1.f;
} else if (outcodeOut & OC_BOTTOM) { // point is below the clip window
v[0] = v0c[0] + (v1c[0] - v0c[0]) * (0.f - v0c[1]) / (v1c[1] - v0c[1]);
v[1] = 0.f;
} else if (outcodeOut & OC_RIGHT) { // point is to the right of clip window
v[1] = v0c[1] + (v1c[1] - v0c[1]) * (1.f - v0c[0]) / (v1c[0] - v0c[0]);
v[0] = 1.f;
} else if (outcodeOut & OC_LEFT) { // point is to the left of clip window
v[1] = v0c[1] + (v1c[1] - v0c[1]) * (0.f - v0c[0]) / (v1c[0] - v0c[0]);
v[0] = 0.f;
}
// Now we move outside point to intersection point to clip
// and get ready for next pass.
if (outcodeOut == outcode0) {
v0c[0] = v[0];
v0c[1] = v[1];
outcode0 = compute_out_code(v0c);
} else {
v1c[0] = v[0];
v1c[1] = v[1];
outcode1 = compute_out_code(v1c);
}
}
}
return accept;
}