chemistry per player in less than 11 player

[motad333]

hi
thanks for coding. its nice but i have issue.
i want to solve foundation sbcs . that required less than 11 player
For example, one of the puzzles requires 3 players and the chemistry is 1 for each player
and players must be 'LW' 'LM' 'ST'
how solve this puzzle with this solver?

[Regista6]

Which SBC is this ?

3 players --> Set NUM_PLAYERS = 3

Chemistry is 1 for each player --> Set CHEMISTRY = 0 and CHEM_PER_PLAYER = 1 and ensure PLAYERS_IN_POSITION = False

Players must be ['LW', 'LM', 'ST'] --> This seems like a weird requirement haha!

Before index is reset at the end in main.py in preprocess_data_2 you can add something like df = df.loc[df['Position'].isin(['LW', 'LM', 'ST'])]

Sometimes these foundations have requirement like Player Level: Exactly Bronze, for that you can do something like df = df[df["Color"] == "Bronze"] in main.py.

If all the 3 players need to be Common then just turn on create_rarity_2_constraint and set RARITY_2 = ["Common"] and NUM_RARITY_2 = [3].

Some work is required as you can see!