Given an absolute path for a file (Unix-style), simplify it. Or in other words, convert it to the canonical path.
In a UNIX-style file system, a period . refers to the current directory. Furthermore, a double period .. moves the directory up a level. For more information, see: Absolute path vs relative path in Linux/Unix
Note that the returned canonical path must always begin with a slash /, and there must be only a single slash / between two directory names. The last directory name (if it exists) must not end with a trailing /. Also, the canonical path must be the shortest string representing the absolute path.
Example 1:
Input: "/home/"
Output: "/home"
Explanation: Note that there is no trailing slash after the last directory name.
Example 2:
Input: "/../"
Output: "/"
Explanation: Going one level up from the root directory is a no-op, as the root level is the highest level you can go.
Example 3:
Input: "/home//foo/"
Output: "/home/foo"
Explanation: In the canonical path, multiple consecutive slashes are replaced by a single one.
Example 4:
Input: "/a/./b/../../c/"
Output: "/c"
Example 5:
Input: "/a/../../b/../c//.//"
Output: "/c"
Example 6:
Input: "/a//b////c/d//././/.."
Output: "/a/b/c"
class Solution(object):
def simplifyPath(self, path):
"""
:type path: str
:rtype: str
"""
# path = '/a/./b/../../c/'
if path == '':
return
path_str = ''
path_list = []
path_lengh = len(path)
i = 0
print ('111', path )
while i < path_lengh:
print ('222', i )
flag = 0
while i < path_lengh and path[i] == '/':
i = i+1
flag = 1
while i < path_lengh and path[i] != '/':
path_str = path_str + path[i]
i = i+1
if flag == 1 and path_str!='':
path_list.append( path_str )
path_str = ''
print ('>>>', path_list)
res_list = []
for index, per in enumerate(path_list):
if per == '.':
continue
elif per == '..':
try:
res_list.pop(-1)
except:
continue
else:
res_list.append(per)
print ('res_list:', res_list)
return '/' + '/'.join(res_list)