假设有一个很长的花坛,一部分地块种植了花,另一部分却没有。可是,花不能种植在相邻的地块上,它们会争夺水源,两者都会死去。
给你一个整数数组 flowerbed 表示花坛,由若干 0 和 1 组成,其中 0 表示没种植花,1 表示种植了花。另有一个数 n ,能否在不打破种植规则的情况下种入 n 朵花?能则返回 true ,不能则返回 false。
输入:flowerbed = [1,0,0,0,1], n = 1
输出:true
输入:flowerbed = [1,0,0,0,1], n = 2
输出:false
let canPlaceFlowers = (flowerbed, n) => {
if (n < 0)
return false;
let cnt = 0;
let len = flowerbed.length;
for (let i = 0; i < len; i++) {
if (flowerbed[i] === 1)
continue;
let pre = i === 0 ? 0 : flowerbed[i - 1];
let next = i === len - 1 ? 0 : flowerbed[i + 1];
if (pre === 0 && next === 0) {
cnt++;
flowerbed[i] = 1;
}
}
return cnt >= n;
};
console.log(canPlaceFlowers([1,0,0,0,1], 1));
console.log(canPlaceFlowers([1,0,0,0,1], 2));
func canPlaceFlower(flowerbed []int, n int) bool {
if n < 0 {
return false
}
cnt := 0
l := len(flowerbed)
for i := 0; i < l; i++ {
if flowerbed[i] == 1{
continue
}
pre, next := 0, 0
if i == 0 {
pre = 0
} else {
pre = flowerbed[i - 1]
}
if i == l - 1 {
next = 0
} else {
next = flowerbed[i + 1]
}
if pre == 0 && next == 0 {
cnt++
flowerbed[i] = 1
}
}
return cnt >= n
}
class Solution {
public boolean canPlaceFlowers(int[] flowerbed, int n) {
// 边界?
if (n < 0) return false;
int cnt = 0;
int len = flowerbed.length;
for (int i = 0; i < len; i++) {
// 判断是1的
if (flowerbed[i] == 1) continue;
int pre = i == 0 ? 0 : flowerbed[i - 1];
int next = i == len - 1 ? 0 : flowerbed[i + 1];
if (pre == 0 && next == 0) {
cnt++;
flowerbed[i] = 1;
}
}
return cnt >= n;
}
}