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<!DOCTYPE html><html lang="zh-CN"><head><meta name="generator" content="Hexo 3.8.0"><meta charset="utf-8"><meta http-equiv="X-UA-Compatible" content="IE=edge"><title>Anoyer's Blog</title><meta name="description" content="一个ACMer的个人博客"><meta name="keywords" content="Anoyer的博客,Anoyer,IT博客,ACM,对数器,后缀自动机"><meta name="HandheldFriendly" content="True"><meta name="apple-mobile-web-app-capable" content="yes"><meta name="viewport" content="width=device-width,initial-scale=1,maximum-scale=1"><meta name="google-site-verification" content="q4xnHYM3-sVfNnyEwMGqknU2CTdojzJvQ5nGfN3EJv8"><link rel="shortcut icon" href="/favicon.ico"><link rel="icon" href="/img/icon.png"><link rel="stylesheet" href="https://use.fontawesome.com/releases/v5.5.0/css/all.css" integrity="sha384-B4dIYHKNBt8Bc12p+WXckhzcICo0wtJAoU8YZTY5qE0Id1GSseTk6S+L3BlXeVIU" crossorigin="anonymous"><link rel="stylesheet" href="//cdn.bootcss.com/Swiper/4.4.6/css/swiper.min.css"><link rel="stylesheet" href="/style.css"><script>var _hmt = _hmt || [];
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href="/statement/index.html">声明</a></li><li><a class="nav-links flat-box nav flat-box" href="/links/index.html">友链</a></li><li><a class="nav-materialplus flat-box nav flat-box" href="https://www.showdoc.cc/xwmp">本站主题</a></li></ul></nav></aside><div><div class="container clearfix"><div class="l_main"><div id="carousel-yc" class="swiper-container"><div class="swiper-wrapper"><div class="swiper-slide"><a href="https://anoyer.cn/categories/2019-Wannafly-Winter-Camp/"><img src="https://img.vim-cn.com/cb/c8ac1c9ea5911645f1500e03833f05a23dbb9b.jpg"></a></div></div><div class="swiper-pagination"></div><div class="swiper-button-prev"></div><div class="swiper-button-next"></div></div><section class="post-list"><div class="post-wrapper"><article class="hover-bgcolor post"><img class="topnew-img" src="/img/top.png"><section class="meta mpost"><div class="cats"><a href="/categories/Hexo/">Hexo</a></div><h2><a title="点击阅读全文" href="/article/Hexo 入门教程.html"><span class="post-title"><b>Hexo的入门教程及Next主题配置</b></span></a></h2><span class="post-data"><i class="fas fa-clock" aria-hidden="true"></i> 2018-11-22-星期四 <i class="fas fa-user" aria-hidden="true"></i> Anoyer </span> </section><section class="typo zdydl"><div><a title="点击阅读全文" href="/article/Hexo 入门教程.html"><img class="post_list_img" src="http://www.005.tv/uploads/allimg/181025/22025KZ4-6.jpg"></a></div><a title="点击阅读全文" style="text-decoration: none" href="/article/Hexo 入门教程.html"><div class="zdya">hexo是什么？简单的说，就是一个静态博客的生成工具也可以说是一个搭建静态博客的框架，我[这个博客](anoyer.cn)就是就是基于hexo生成的。9月份把这个博客用hexo折腾出来，前几天ACM区域赛事结束了，所以想记录下来折腾的</div></a></section></article></div><div class="post-wrapper"><article class="hover-bgcolor post"><img class="topnew-img" src="/img/top.png"><section class="meta mpost"><div class="cats"><a href="/categories/闲记/">闲记</a></div><h2><a title="点击阅读全文" href="/article/Anoyer训练计划.html"><span class="post-title"><b>Anoyer训练计划</b></span></a></h2><span class="post-data"><i class="fas fa-clock" aria-hidden="true"></i> 2018-11-30-星期五 <i class="fas fa-user" aria-hidden="true"></i> Anoyer </span> </section><section class="typo zdydl"><div><a title="点击阅读全文" href="/article/Anoyer训练计划.html"><img class="post_list_img" src="http://www.005.tv/uploads/allimg/180919/0410235545-6.jpg"></a></div><a title="点击阅读全文" style="text-decoration: none" href="/article/Anoyer训练计划.html"><div class="zdya">前期：18年12月-19年2月低完成算法专题训练一阶段+一些专题散题，kuangbin-字符串所有专题:kuangbin-数论所有专题,各OJ专题散题+cf比赛,该阶段必须掌握字符串和数论所有考点算法及其各种运用(这也是刷专题的意义所在），除去一些特难算法稀有神兽级别的算法（脑子不够，学意义也不大）</div></a></section></article></div><div class="post-wrapper"><article class="hover-bgcolor post"><img class="topnew-img" src="/img/top.png"><section class="meta mpost"><div class="cats"><a href="/categories/Pyhton/">Pyhton</a></div><h2><a title="点击阅读全文" href="/article/Python入门教程.html"><span class="post-title"><b>Python入门教程</b></span></a></h2><span class="post-data"><i class="fas fa-clock" aria-hidden="true"></i> 2018-12-02-星期日 <i class="fas fa-user" aria-hidden="true"></i> Anoyer </span> </section><section class="typo zdydl"><div><a title="点击阅读全文" href="/article/Python入门教程.html"><img class="post_list_img" src="https://img.vim-cn.com/8a/875c0eff402f2af707d36b5897d561005692ab.jpg"></a></div><a title="点击阅读全文" style="text-decoration: none" href="/article/Python入门教程.html"><div class="zdya">Python入门教程...未使用C等语言的花括号，而是采用缩进的方式表示层次关系...按照先后顺序一条一条执行循环条件满足就反复执行，不满足就不执行或者不再执行例如：先洗手，看饭好了没有，没有好，一会来看一次是否好了，一会儿来看一次，直到饭好了，才可以吃饭。这里循环的条件就是饭好了没，饭没好，就循环</div></a></section></article></div><div class="post-wrapper"><article class="hover-bgcolor post"><section class="meta mpost"><div class="cats"><a href="/categories/题解/">题解</a></div><h2><a title="点击阅读全文" href="/article/henau-0310.html"><span class="post-title"><b>河南农大算法训练赛三月周赛-0310</b></span></a></h2><span class="post-data"><i class="fas fa-clock" aria-hidden="true"></i> 2019-03-10-星期日 <i class="fas fa-user" aria-hidden="true"></i> Anoyer </span> </section><section class="typo zdydl"><div><a title="点击阅读全文" href="/article/henau-0310.html"><img class="post_list_img" src="https://img.vim-cn.com/88/ab8d80750c4470ba81ab97e539de59ec7b0baa.jpg"></a></div><a title="点击阅读全文" style="text-decoration: none" href="/article/henau-0310.html"><div class="zdya">题意：给一个字符串，如果大写数比小写数多，全部转化成大写，否则全部小写。题解：遍历一遍字符串，用cnts和cntb记录大小写数量，最后对比调用strupr,strlwr</div></a></section></article></div><div class="post-wrapper"><article class="hover-bgcolor post"><section class="meta mpost"><div class="cats"><a href="/categories/题解/">题解</a></div><h2><a title="点击阅读全文" href="/article/zzuli-302.html"><span class="post-title"><b>ZZULI-2019年3月份月赛（个人赛）EF题解</b></span></a></h2><span class="post-data"><i class="fas fa-clock" aria-hidden="true"></i> 2019-03-03-星期日 <i class="fas fa-user" aria-hidden="true"></i> Anoyer </span> </section><section class="typo zdydl"><div><a title="点击阅读全文" href="/article/zzuli-302.html"><img class="post_list_img" src="https://img.vim-cn.com/5d/a8a47878b26eafd3b5ca054c29a5ed825730d2.jpg"></a></div><a title="点击阅读全文" style="text-decoration: none" href="/article/zzuli-302.html"><div class="zdya">给一段01串从任意位置进行截取，问最多能截取出多少个7位串对应字母的ASCLL值.题解：利用map将所有字母的7位ASCALL值存起来，然后对字符串进行暴力7位一截取。看看截取出来的串是否是字母的ASCALL值，如果是则位置i+6（因为有for里i++，会再加1</div></a></section></article></div><div class="post-wrapper"><article class="hover-bgcolor post"><section class="meta mpost"><div class="cats"><a href="/categories/题解/">题解</a></div><h2><a title="点击阅读全文" href="/article/UVA-11624-Fire.html"><span class="post-title"><b>UVA - 11624 - Fire!(BFS逃生问题)</b></span></a></h2><span class="post-data"><i class="fas fa-clock" aria-hidden="true"></i> 2019-02-25-星期一 <i class="fas fa-user" aria-hidden="true"></i> Anoyer </span> </section><section class="typo zdydl"><div><a title="点击阅读全文" href="/article/UVA-11624-Fire.html"><img class="post_list_img" src="https://img.vim-cn.com/41/2c5f9e78331621ae7159163d7fcbc635a5393b.jpg"></a></div><a title="点击阅读全文" style="text-decoration: none" href="/article/UVA-11624-Fire.html"><div class="zdya">在迷宫内，J表示人，F表示火，火可能不止一处，但是人只有一个，火会向上下左右蔓延，蔓延速度和人移动速度一至（每次一格，但是可以同时向四个方向）问是否可以成功逃出迷宫，不能输出IMPOSSIBLE，能的画话输出最短路径。</div></a></section></article></div><div class="post-wrapper"><article class="hover-bgcolor post"><section class="meta mpost"><div class="cats"><a href="/categories/题解/">题解</a></div><h2><a title="点击阅读全文" href="/article/POJ-3984.html"><span class="post-title"><b>POJ - 3984 - 迷宫问题(路径记录)</b></span></a></h2><span class="post-data"><i class="fas fa-clock" aria-hidden="true"></i> 2019-02-25-星期一 <i class="fas fa-user" aria-hidden="true"></i> Anoyer </span> </section><section class="typo zdydl"><div><a title="点击阅读全文" href="/article/POJ-3984.html"><img class="post_list_img" src="https://img.vim-cn.com/cb/5169844b6a378284cf05a542a05c5d027ed2c8.jpg"></a></div><a title="点击阅读全文" style="text-decoration: none" href="/article/POJ-3984.html"><div class="zdya">给你一个5*5的迷宫，0代表通路，1代表墙，找到从迷宫左上角到达右下角的最短路径，并输出路径。先进行一遍BFS，得到vis数组，表示到该位置最少需要多少时间，然后从(4,4)位置倒着查路径,查到符合的就直接break，防止重复</div></a></section></article></div><div class="post-wrapper"><article class="hover-bgcolor post"><section class="meta mpost"><div class="cats"><a href="/categories/题解/">题解</a></div><h2><a title="点击阅读全文" href="/article/POJ-3278-Catch-That-Cow.html"><span class="post-title"><b>POJ - 3278 - Catch That Cow(裸BFS)</b></span></a></h2><span class="post-data"><i class="fas fa-clock" aria-hidden="true"></i> 2019-02-25-星期一 <i class="fas fa-user" aria-hidden="true"></i> Anoyer </span> </section><section class="typo zdydl"><div><a title="点击阅读全文" href="/article/POJ-3278-Catch-That-Cow.html"><img class="post_list_img" src="http://www.005.tv/uploads/allimg/181105/1F1431Q4-16.jpg"></a></div><a title="点击阅读全文" style="text-decoration: none" href="/article/POJ-3278-Catch-That-Cow.html"><div class="zdya">给定两个整数n和k，通过 n+1或n-1 或n*2 这3种操作，使得n==k，输出最少的操作次数.简单的对每个节点进行三个方向（三种走法）的BFS</div></a></section></article></div><div class="post-wrapper"><article class="hover-bgcolor post"><section class="meta mpost"><div class="cats"><a href="/categories/题解/">题解</a></div><h2><a title="点击阅读全文" href="/article/POJ-3126-Prime-Path.html"><span class="post-title"><b>POJ - 3126 - Prime Path(BFS枚举)</b></span></a></h2><span class="post-data"><i class="fas fa-clock" aria-hidden="true"></i> 2019-02-25-星期一 <i class="fas fa-user" aria-hidden="true"></i> Anoyer </span> </section><section class="typo zdydl"><div><a title="点击阅读全文" href="/article/POJ-3126-Prime-Path.html"><img class="post_list_img" src="https://img.vim-cn.com/ca/dc0a3ad2d8313348fd6de3d1bec61c5c1d25bc.jpg"></a></div><a title="点击阅读全文" style="text-decoration: none" href="/article/POJ-3126-Prime-Path.html"><div class="zdya">给出两个四位数的素数a,b，求从a变到b最少要花几步？每一步只能将a中的一位改变，且改变后的数也要是素数。BFS枚举个位，十位，百位，千位变换的数，用素数表判断变换后是否为一个素数</div></a></section></article></div><div class="post-wrapper"><article class="hover-bgcolor post"><section class="meta mpost"><div class="cats"><a href="/categories/题解/">题解</a></div><h2><a title="点击阅读全文" href="/article/POJ-3087-Shuffle-m-Up.html"><span class="post-title"><b>POJ - 3087 - Shuffle'm Up(模拟)</b></span></a></h2><span class="post-data"><i class="fas fa-clock" aria-hidden="true"></i> 2019-02-25-星期一 <i class="fas fa-user" aria-hidden="true"></i> Anoyer </span> </section><section class="typo zdydl"><div><a title="点击阅读全文" href="/article/POJ-3087-Shuffle-m-Up.html"><img class="post_list_img" src="https://img.vim-cn.com/c4/edc2eb3cf7d9f60243659bc05cfbca4b6958b2.jpg"></a></div><a title="点击阅读全文" style="text-decoration: none" href="/article/POJ-3087-Shuffle-m-Up.html"><div class="zdya">已知两堆牌s1和s2的初始状态,其牌数均为c,按给定规则能将他们相互交叉组合成一堆牌s12,再将s12的最底下的c块牌归为s1,最顶的c块牌归为s2,依此循环下去.现在输入s1和s2的初始状态以及预想的最终状态s12</div></a></section></article></div></section><br><div class="prev-next"><div class="prev-next"><p class="current">1 / 11</p><a class="next" rel="next" href="/page/2/"><section class="post next"> 下一页 <i class="fa fa-chevron-right" aria-hidden="true"></i></section></a></div></div></div><aside class="l_side"><section class="m_widget author"><div class="header"><img class="avatar" src="/img/author.png"></div><div class="content"><center><h1>Anoyer</h1></center><div><center><span>今日的我要超越昨日的我，明日的我要胜过今日的我</span></center></div></div><div class="social-wrapper"><a style="background-color: #27ccc0" title="邮箱" href="mailto:[email protected]" class="social-icon flat-box" target="_blank" rel="external"><i class="fas fa-envelope" aria-hidden="true"></i></a> <a style="background-color: #12b7f5" title="QQ(1316895941)" href="http://wpa.qq.com/msgrd?v=3&uin=1316895941&site=qq&menu=yes" class="social-icon flat-box" target="_blank" rel="external"><i class="fab fa-qq" aria-hidden="true"></i></a> <a style="background-color: #f45a8d" title="CSDN" href="https://me.csdn.net/Anoy_acer" class="social-icon flat-box" target="_blank" rel="external"><i class="fab 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